Question

解一道分式方程,1/（x+5)+1/(x+8)=1/(x+6)+1/(x+7)做到(2x+13){(x+6)(x+7)-

Answer 1

1/(x+5)+1/(x+8)=1/(x+6)+1/(x+7)

(x+6)(x+7)(x+8)+(x+6)(x+7)(x+5)=(x+5)(x+7)(x+8)+(x+5)(x+6)(x+8)

[(x+6)(x+7)]([x+8)+(x+5)]=[(x+5)(x+8)][(x+6)+(x+7)]

[(x+6)(x+7)](2x+13)=[(x+5)(x+8)](2x+13)

(2x+13){(x+6)(x+7)-(x+5)(x+8)]=0

2x+13=0

x=-13/2