∵∠CFG=∠EFG且FH平分∠BFE.
∠GFH=∠EFG+∠EFH
∴∠GFH=∠EFG+∠EFH=
1
2 ∠EFC+
2 ∠EFB=
2 (∠EFC+∠EFB)=
2 ×180°=90°.
故选C.