Question

数学高手进来,要快啊!已知二次函数f(X)=ax^2+bx+c,当x=1/2时.y的最小值为-49/4,且方程ax^2+

Answer 1

x1+x2=1

x1-x2=7

x1 =4

x2 = -3

f(x)=(x-4)(x+3)=x^2-x-12

a=1

b=-1

c=-12