x/2=y/3=z/4=k x=2k y=3k z=4k (2x+3y-z)/(x-3y+z) =(4k+9k-4k)/(2k-9k+4k) =9k/(-3k) =-3
已知x/2=y/3=z/4且xyz不等于0,求2x+3y-z/x-3y+z拜托各位了 3Q
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