Question

求f(x-1)=(x-1)(x-2) 的单调区间

Answer 1

f(x-1)=(x-1)(x-2)

f(x)=x(x+1)

f'(x) = 2x+1

f'(x) =0

2x+1=0

x=-1/2

f''(x) =2 >0 (min)

f(x)

递增 = (-∞,-1/2]

递减 =[-1/2,∞)