Question

计算[2x/(x-1)-3x/(x+1)÷x/x^2-1 分解因式：x^3y-xy^3 x^2-16x+64

Answer 1

[2x/(x-1)-3x/(x+1)]÷x/(x^2-1)=x[2(x+1)-3(x-1)](x²-1)/[x(x²-1)]=2x+2-3x+3=5-3x

x^3y-xy^3 =xy(x²-y²)=xy(x+y)(x-y)

x²-16x+64=x²-2*8x+8²=(x-8)²