Question

已知抛物线y²＝6x,求以点M（4,1）为中点的弦所在的直线方程,就过焦点F的弦的弦的中点轨迹方程

Answer 1

M（4,1）为中点的弦AB

yA+yB=2yM=2*1=2

k(AB)=(yA-yB)/(xA-xB)=(y-1)/(x-4)

(yA)^2-(yB)^2=6(xA-xB)

(yA+yB)*(yA-yB)/(xA-xB)=6

2*(y-1)/(x-4)=6

3x-y-11=0