Question

整式的计算.1. 已知a^3n=5 b^2n=3 求a^6n b^4n的值2.设n为正整数且x^2n=2 求9（x^3n

Answer 1

1.a^6n=a^(2x3n)=(a^3n)^2=5^2=25

b^4n=(b^2n)^2=3^2=9

2.x^6n=(x^2n)^3=2^3=8

9(x^3n)^2=9（x^6n)=9x8=72

3.2^3m=(2^m)^3=a^3

32^n=(2^5)^n=2^5n

2^10n=(2^5n)^2=b^2

2^(3m+10n)=2^3mX2^10n=a^3b^2