Question

如图所示,将长方形纸片ABCD折叠,使点D与点B重合,点C落在点C′处,折痕为EF,若∠BFE=55°求∠AEB的度数

Answer 1

∵AD∥BC,

∴∠DEF=∠BFE=55°,

又∵折叠,

∴∠BEF=∠DEF=55°,

∴∠AEB=180°-∠BEF-∠FED

=180°-55°-55°

=70°