y=cos(x)^X
设,u=cos(x),
v=u^x,则有
y'=u^x*lnu*u'
=u^x*lnu*(-sin(x))
=-cos(x)^x*(lncosx)*sin(x).
y=cos(x)x平方.求y'y=cos(x)^x.求y'
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