设函数f(x)=sin(wx-π/6)-2cos平方w/2乘以x+1(w>0)直线y=f(x)图像相邻两交点的距离为π,则函数y=f(x)区间【0,π】上的单调增区间为,
解析:∵函数f(x)=sin(wx-π/6)-2(cos(wx/2))^2+1=sin(wx-π/6)-coswx=√3sin(wx-π/3)
∵y=f(x)图像相邻两交点的距离为π
∴T/2=π==>T=2π==>w=1
∴f(x)=√3sin(x-π/3)
2kπ-π/2
设函数f(x)=sin(wx-π/6)-2cos平方w/2乘以x+1(w>0)直线y=f(x)图像相邻两交点的距离为π,则函数y=f(x)区间【0,π】上的单调增区间为,
解析:∵函数f(x)=sin(wx-π/6)-2(cos(wx/2))^2+1=sin(wx-π/6)-coswx=√3sin(wx-π/3)
∵y=f(x)图像相邻两交点的距离为π
∴T/2=π==>T=2π==>w=1
∴f(x)=√3sin(x-π/3)
2kπ-π/2