因式分解求值题①;已知a+b=4,ab=3,求a³b-a²b²+ab³的值②;如

5个回答

  • ①;已知a+b=4,ab=3,求a³b-a²b²+ab³的值

    a³b-a²b²+ab³

    =ab(a²-ab+b²)

    =ab[(a+b)²-3ab]

    =3(4²-3*3)

    =3*7

    =21

    ②;如果多项式4x²+mx+25是完全平方式,求m的值

    4x²+mx+25

    =(2x+5)²

    =4x²+20x+25

    m=20

    ③;已知a²+b²+4a-2b+5=0,求a,b的值

    a²+b²+4a-2b+5=0

    a²+4a+4+b²-2b+1=0

    (a+2)²+(b-1)²=0

    a+2=0

    a=-2

    b-1=0

    b=1

    ④;已知x-y=4,y-z=2,求x²y+y²z+z²x-(xy²+yz²+zx²)

    x²y+y²z+z²x-(xy²+yz²+zx²)

    =x²y-xy²+y²z-yz²+z²x-zx²

    =xy(x-y)+yz(y-z)+xz(z-x)

    =4xy+2yz+xz(z-x)

    x-y=4

    x=4+y

    y-z=2

    y=2+z (1)

    x=6+z (2)

    把(1)(2)代入上式

    原式=4(6+z)(2+z)+2(2+z)z+(6+z)z(z-6-z)

    =4(12+8z+z²)+4z+2z²-6z(6+z)

    =48+32z+4z²+4z+2z²-36z-6z²

    =48

    ⑤;已知(a+b)²=8,(a-b)²=4,求a²+b²和ab的值

    (a+b)²-(a-b)²

    =a²+2ab+b²-a²+2ab-b²

    =4ab

    =8-4

    =4

    ab=1

    (a+b)²=8

    a²+b²+2ab=8

    a²+b²=8-2ab

    =8-2*2

    =4

    ⑥;先化简,再求值:[(x-y)²+(x+y)(x-y)]除以2x,其中x=3,y=-1.5

    [(x-y)²+(x+y)(x-y)]/2x

    =(x²-2xy+y²+x²-y²)/2x

    =(2x²-2xy)/2x

    =[2x(x-y)]/2x

    =x-y

    把x=3,y=-1.5代入上式

    原式=3-(-1.5)

    =4.5