解由f(x)=(x+2)/(x-6)
(1)当x=3时,f(3)=(3+2)/(3-6)=-5/3,即点(3,14)不在f(x)的图像上
(2)当x=4时,f(4)=(4+2)/(4-6)=-3
(3)当f(x)=2时,即(x+2)/(x-6)=2,即x+2=2x-12,即x=14.
解由f(x)=(x+2)/(x-6)
(1)当x=3时,f(3)=(3+2)/(3-6)=-5/3,即点(3,14)不在f(x)的图像上
(2)当x=4时,f(4)=(4+2)/(4-6)=-3
(3)当f(x)=2时,即(x+2)/(x-6)=2,即x+2=2x-12,即x=14.