由题意,f(x)=6cos^2x-2√3sinxcosx,
化简得,f(x)=3cos2x -√3sin2x +3,
即有f(α)=3cos2α -√3sin2α +3=3-2√3,
化简得,1/2·sin2α -√3/2·cos2α=1,
可得,sin(2α-π/3)=1,
有2α-π/3=2kπ+π/2,k∈N,
∵ α
由题意,f(x)=6cos^2x-2√3sinxcosx,
化简得,f(x)=3cos2x -√3sin2x +3,
即有f(α)=3cos2α -√3sin2α +3=3-2√3,
化简得,1/2·sin2α -√3/2·cos2α=1,
可得,sin(2α-π/3)=1,
有2α-π/3=2kπ+π/2,k∈N,
∵ α