Question

甲酸电离常数计算:0.2mol/L甲酸溶液,3.2%电离,

Answer 1

-----------HA = H+ + A-

初始：C 0 0

平衡：C- 3.2%C 3.2%C 3.2%C

[H+][A-]/[HA] = K = 3.2%C * 3.2%C / (C- 3.2%C )

C = 0.2 代入求出K即可.