Question

若a,b互为相反数,x,y互为倒数,|m|=2,且ab≠0,则代数式xym(a+b)+(-a分之b)^3+(a-xy+b

Answer 1

a,b互为相反数 A+B=0

,x,y互为倒数 xy=1

xym(a+b)+(-a分之b)^3+(a-xy+b)^2

=0+(1)^3+1^2

=2