3xy-2x-12y+8和a²-b²+6b-9.
2个回答
3xy-2x-12y+8=x(3y-2)-4(3y-2)=(3y-2)(x-4)
a2-b2+6b-9=a2-(b2-6b+9)=a2-(b-3)2=(a-b+3)(a+b-3)
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