方程x²-2x-1=0的两根
是x1=1+√2;x2= 1-√2
a=1+√2;b=1-√2
或a=1-√2;b=1+√2
4b-2b+a³=2b+a³=2-2√2+(1+√2)³=9+3√2
或4b-2b+a³=2b+a³=2+2√2+(1-√2)³=9-3√2
方程x²-2x-1=0的两根
是x1=1+√2;x2= 1-√2
a=1+√2;b=1-√2
或a=1-√2;b=1+√2
4b-2b+a³=2b+a³=2-2√2+(1+√2)³=9+3√2
或4b-2b+a³=2b+a³=2+2√2+(1-√2)³=9-3√2