BC的中点是:(-5/2,1)
∴中线AD方程为:(y-5)/(1-5)=(x-0)/(-5/2-0),整理得:8x-5y+25=0
AB中点E(1/2,3/2),AC中点F(-3,9/2)
∴中位线EF方程为:(y-3/2)/(9/2-3/2)=(x-1/2)/(-3-1/2),整理得:12x+14y-27=0
BC的中点是:(-5/2,1)
∴中线AD方程为:(y-5)/(1-5)=(x-0)/(-5/2-0),整理得:8x-5y+25=0
AB中点E(1/2,3/2),AC中点F(-3,9/2)
∴中位线EF方程为:(y-3/2)/(9/2-3/2)=(x-1/2)/(-3-1/2),整理得:12x+14y-27=0