Question

已知x²-4x+y²-10y+29=0求x²+2x³y²+x̾

Answer 1

x²-4x+y²-10y+29=0

x²-4x+4+y²-10y+25=0

(x-2)²+(y-5)²=0

(x-2)²=0,(y-5)²=0

x=2

y=5

x²+2x³y²+x⁴y²

=x²(1+2xy²+x²y²)

=2²*(1+2*2*5²+2²*5²)

=4*(1+100+100)

=4*201

=804