Question

已知|a+1/2|+(b-3)^2=0,求[(2x+b)^2]-(b+2a)(2a-b)-6b]÷2b的值

Answer 1

提示：

|a+1/2|+(b-3)^2=0

|a+1/2|=0,a=-1/2

(b-3)^2=0,b=3

求[(2x+b)^2]-(b+2a)(2a-b)-6b]÷2b的值,我相信你会的!