已知当X=1时,多项式ax5+bx4+cx3+dx2+ex+4的值等于5,则代数式a+b+c+d+e的值是多少
3个回答
x=1
ax5+bx4+cx3+dx2+ex+4
=a+b+c+d+e+4=5
a+b+c+d+e=1
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