∵∠B+∠BCF=∠F+∠FEB,∠D+∠DEF=∠F+∠FCD
两式相加∵∠B+∠BCF+∠D+∠DEF==∠F+∠FEB+∠F+∠FCD
∵∠BCF=∠FCD,∠BEF=∠DEF
∴∠B+∠D=2∠F
当∠B:∠D:∠F=2:4:x时,2+4=2x,
解得x=3
∵∠B+∠BCF=∠F+∠FEB,∠D+∠DEF=∠F+∠FCD
两式相加∵∠B+∠BCF+∠D+∠DEF==∠F+∠FEB+∠F+∠FCD
∵∠BCF=∠FCD,∠BEF=∠DEF
∴∠B+∠D=2∠F
当∠B:∠D:∠F=2:4:x时,2+4=2x,
解得x=3