Question

已知：3a-b+1的绝对值+（2a-b)^2=0,求(b^2/a+b)*(ab/a+b)的值

Answer 1

3a-b+1=0

2a-b=0

则a=-1,b=-2

[b^2/(a-b)]/{[b/(a-b)][ab/(a+b)]}

=[b^2/(a-b)][(a-b)^2/(ab^2)]

=(a-b)/a

=(-1+2)/(-1)

=-1