Question

(根号下x-3)+(y的平方)-(2/3)y+1/9=0,求 √x+√y/x+√xy的值为

Answer 1

即根号(x-3)+(y-1/3)^2=0

所以x-3=0,y-1/3=0

x=3,y=1/3

所以原式=√3+√(1/9)+√1

=√3+1/3+1

=√3+4/3