为了你能看明白,我尽量不跳步
f(x)=2cosxsin(x+π/6)+√3sinxcosx-sin²x
= 2cosx[sinxcos(π/6)+cosxsin(π/6)]+√3sinxcosx-sin²x
= 2cosx(√3sinx/2+1/2cosx)+√3sinxcosx-sin²x
=√3sinxcosx+cos²x+√3sinxcosx-sin²x
=2√3sinxcosx+cos²x-sin²x
=√3sin(2x)+cos(2x)
=2[√3/2sin(2x)+1/2sin(2x)]
=2sin(2x+π/6)
由-π/2+2kπ