[X+Y]的平方-Y〔2X+Y)-8X〕除以2X
5个回答
[X+Y]的平方-Y〔2X+Y)-8X〕除以2X
=[(x^2+2xy+y^2)-(2xy+y^2)-8x]/2x
=[x^2-8x]/2x
=x/2-4
=(1/2*x)-4
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