Question

已知数列{an}满足a1=0,a2=2,且对任意m'n属于N*,都有a(2m-1)+a(2n+1)=2a(m+n-1)+

Answer 1

a(2n-1)+a(2n+1)=2a(n+n-1)+0=2a(2n-1),

a(2n+1)=a(2n-1)=...=a(1)=0.

a(2n-1)=0.

a[2(n+1)-1] + a(2n+1) = 2a(n+1 + n-1) + 2(n+1-n)^2,

a(2n+1) + a(2n+1) = 0 = 2a(2n) + 2,

a(2n)=-1, 与a(2)=2矛盾哈.

题目有问题吧...