Question

解方程：[（x²-3x)/(x²-1）]+[(2x-1)/(x-1)]=0

Answer 1

解析：由题意可知x≠1且x≠-1,那么：原方程两边同乘以x²-1可得：x²-3x+(2x-1)(x+1)=0x²-3x+2x²+x-1=0即3x²-2x-1=0(3x-1)(x+1)=0因为x≠-1,即x+1≠0,所以：解上述方程可得x=1/3即原方程的解...