Question

八年级下分式的加减法第一题：已知abc=1,求a/ab+a+1 + b/bc+b+1 + c/ca+c+1的值.第二题：

Answer 1

1、

a/ab+a+1 =a/ab+a+abc = 1/b+1+bc

所以,a/ab+a+1 + b/bc+b+1 =1+b/bc+b+1 = abc+b/bc+b+abc

= ac+1/c+1+ac

所以,原式= ac+1/c+1+ac + c/ca+c+1 =1

2、

原式=a/b + a/c + b/c+ b/a +c/a + c/b +3

=a+c/b + a+b/c + b+c/a + 3

=-b/b -c/c -a/a + 3

=0