Question

若2m=3n,求分式（1+m/n-n/n-m)除以（1-m/n-n/n+m)的值

Answer 1

∵2m=3n

∴m/n=3/2

令 m=3k n=2k (k≠0)

那么

[1+m/n-n/(n-m)]/[1-m/n-n/(n+m)]

=(1+3/2+2)/(1-3/2-2/5)

=(9/2)/(9/10)

=5