f(x)=sinx/2cosx/2+根号3sinx

f(x)=sinx/2cosx/2+根号3sinx/2的平方+根号3/2.求单调增区间

2个回答

f(x)=sin(x/2)cos(x/2)+√3sin²(x/2)+√3/2
=1/2sinx-√3/2(1-2sin²(x/2))+√3/2+√3/2
=1/2sinx-√3/2cosx+√3
=sin(x-π/3)+√3
单增区间：2kπ-π/2