∵(a-b)/(a+b)=½
∴(a+b)/(a-b)=2
(a+b)/[3(a-b)]-(a-b)/[2(a+b)]
=(1/3)[(a+b)/(a-b)]-(½)[(a-b)/(a+b)]
=(1/3)×2-(½)×(½)
=(2/3)-(¼)
=5/12
∵(a-b)/(a+b)=½
∴(a+b)/(a-b)=2
(a+b)/[3(a-b)]-(a-b)/[2(a+b)]
=(1/3)[(a+b)/(a-b)]-(½)[(a-b)/(a+b)]
=(1/3)×2-(½)×(½)
=(2/3)-(¼)
=5/12