(m+1)+(2n-1)=5 (1)
(n+2)+(2m)=3 (2)
由(2) :n+2+2m=3
n+2m =3-2
n+2m =1
n =1-2m (3)
(3)代入(1) m+1 +2n-1=5
m+2n =5
m+2(1-2m)=5
m+2-4m =5
-3m =5-2
-3m =3
m=-1
n=1-2m
n=1-2(-1)
n=1+2
n=3
m=-1 ,n=3
(m+1)+(2n-1)=5 (1)
(n+2)+(2m)=3 (2)
由(2) :n+2+2m=3
n+2m =3-2
n+2m =1
n =1-2m (3)
(3)代入(1) m+1 +2n-1=5
m+2n =5
m+2(1-2m)=5
m+2-4m =5
-3m =5-2
-3m =3
m=-1
n=1-2m
n=1-2(-1)
n=1+2
n=3
m=-1 ,n=3