设C坐标为(0,x)
AB^2=25 AC^2=4+x^2 BC^2=4+(3+x)^2
∠ACB=90° 知AB^2=AC^2+BC^2
则25=4+x^2+4+(3+x)^2=17+6x+2x^2
=>2x^2+6x-8=0
=>x^2+3x-4=(x-1)(x+4)=0
=>x1=1 x2=-4
所以C坐标为(0,1) (0,-4)
设C坐标为(0,x)
AB^2=25 AC^2=4+x^2 BC^2=4+(3+x)^2
∠ACB=90° 知AB^2=AC^2+BC^2
则25=4+x^2+4+(3+x)^2=17+6x+2x^2
=>2x^2+6x-8=0
=>x^2+3x-4=(x-1)(x+4)=0
=>x1=1 x2=-4
所以C坐标为(0,1) (0,-4)