K2Cr2O7+CH3CH2OH+H2SO4--Cr2(SO4)3+CH3COOH+K2SO4+H2O
1个回答
配平为2,3,8,2,3,2,11
CH3CH20H中第二个C失去电子4e CH3COOH中第二个C得到电子4e
相关问题
K2CrO7+CH3CH2OH+H2SO4==Cr2(SO4)3+CH3COOH+K2SO4+H2O
2K2Cr2O7+3CH3CH2OH+8H2SO4--2Cr2(SO4)3+ 3CH3COOH+2K2SO4+11H2O
2K2Cr2O7+3CH3CH2OH+8H2SO4=2Cr2(SO4)3+3CH3COOH+2K2SO4+11H2O 的
高一化学问题2K2Cr2O7+3CH3CH2OH+8H2SO4=2K2SO4+2Cr2(SO4)3+3CH3COOH+1
配平:K2Cr2O7+C2H5OH+H2SO4=Cr2(SO4)3+CH3COOH+K2SO4+_____(此物质未知)
K2Cr2O7与乙醇的反应.K2Cr2O7与乙醇 2K2Cr2O7+3CH3CH2OH+8H2SO4--2Cr2(SO4
2K2Cr2O7+3C2H5OH+8H2SO4=2K2SO4+2Cr(SO4)3+3CH3COOH+11H2O是否为还原
K2Cr2O7+H2SO4+K2SO3=K2SO4+Cr2(SO4)3+H2O
a K2Cr2O7(橙红色)+ b C2H5OH+ c H2SO4 ====d CR2(SO4)3(绿色)+ e CH3
H2SO4+CH3OH+K2Cr2O4反应的方程式怎么写