Question

{2(y-2)}^2-4(y-2)(3y+7)≥0 怎么解得-9/2≤ y

Answer 1

[2(y - 2)]² - 4(y - 2)(3y + 7) ≥ 0

4(y - 2)² - 4(y - 2)(3y + 7) ≥ 0

4(y - 2)(y - 2 - 3y - 7) ≥ 0

4(y - 2)(-2y - 9) ≥ 0

4(y - 2)(2y + 9) ≤ 0

-9/2 ≤ y ≤ 2