用十字分解法1.(2x的平方-3x-1)的平方-22x的平方+33x-12.(6x+7)的平方(3x+4)(x+1)-6

1个回答

  • 1.

    (2x^2-3x-1)^2-22x^2+33x+11-12

    =(2x^2-3x-1)^2-11(2x^2-3x-1)-12

    =(2x^2-3x-1+1)(2x^2-3x-1-12)

    =(2x^2-3x)(2x^2-3x-13)

    =x(2x-3)(2x^2-3x-13)

    2.

    (6x+7)^2(3x+4)(x+1)-6

    =(36x^2+84x+49)(3x^2+7x+4)-6

    =108x^4+252x^3+144x^2+252x^3+588x^2+336x+147x^2+343x+196-6

    =108x^4+504x^3+291x^2+679x+190

    =

    3.

    (a+b-2ab)(a+b-2)+(1-ab)^2

    =(a+b)^2-2(a+b)-2ab(a+b)+4ab+(1-ab)^2

    =(a+b)^2-2(a+b)(1+2ab)+(1+ab)^2

    =(a+b-1-ab)^2

    =(a-1)^2(b-1)^2

    (x+1)(x+6)(x+2)(x+3)+x^2

    =(x^2+7x+6)(x^2+5x+6)+x^2

    =(x^2+6)^2+12x(x^2+6)+35x^2+x^2

    =(x^2+6)^2+12x(x^2+6)+36x^2

    =(x^2+6+6x)^2

    (a-b)(x-y)(x+y)-(x-y)(a-b)(a+b)

    =(a-b)(x-y)(x+y-a-b)