求不定积分xtan^2 xdx
1个回答
∫xtan²xdx
=∫x(sec²x-1)dx
=∫xsec²xdx-∫xdx
=∫xdtanx-∫xdx
=xtanx-∫tanxdx-∫xdx
=xtanx+㏑|cosx|-x²/2+C
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