x=a(tanθ+1/cosθ)
= a(sinθ+1)/cosθ
= y*(sinθ+1)
即 sinθ = x/y - 1
又 y=a/cosθ 即 cosθ = a/y
由sin²θ+cos²θ=1得
(x/y - 1)² +a²/y² = 0
(x-y)²+a² = 0
x=a(tanθ+1/cosθ)
= a(sinθ+1)/cosθ
= y*(sinθ+1)
即 sinθ = x/y - 1
又 y=a/cosθ 即 cosθ = a/y
由sin²θ+cos²θ=1得
(x/y - 1)² +a²/y² = 0
(x-y)²+a² = 0