Question

[化学有机]关于甲烷密度计算隔绝空气强热甲烷,可分解成C2H2和H2.若1mol甲烷有80%按上述形式分解,所得混合气体

Answer 1

若1mol甲烷有80%按上述形式分解:

n(CH4) = 1*(1-80%) =0.2mol

n(CH2) = n(H2) = 0.8mol

n= 0.2+0.8*2 = 1.8mol

16g/1.8mol = 8.89 g/mol

He :4g/mol

8.89/4 = 2.22

B