25a的4次方-a²
=a²(25a²-1)
=a²(5a+1)(5a-1)
(2a-1)²-2a+1
=(2a-1)²-(2a-1)
=[(2a-1)-1](2a-1)
=(2a-2)(2a-1)
=2(a-1)(2a-1)
明白请采纳,有疑问请追问!
有新问题请求助,谢谢!
25a的4次方-a²
=a²(25a²-1)
=a²(5a+1)(5a-1)
(2a-1)²-2a+1
=(2a-1)²-(2a-1)
=[(2a-1)-1](2a-1)
=(2a-2)(2a-1)
=2(a-1)(2a-1)
明白请采纳,有疑问请追问!
有新问题请求助,谢谢!