Question

log16(27)=a,求log9(96)

Answer 1

log16(27)=a

=>lg3=alg2

log9(96)=log9(16)+log9(6)

=[lg16+lg6]/lg9

=[4lg2+lg3+lg2]/2lg3

=[5lg2+lg3]/2lg3

=([5lg2+alg2)/2alg2

=(5+a)/2a