2222×1+2222×6+2222×2+2222×5+2222×3+2222×4+…………
=2222×(1+6)+2222×(2+5)+2222×(3+4)+…………
括号内除以7均能整除 所以同理 最后剩了2222×2220+2222×2221+2222×2222=2222×(2220+2221+2222)=2222×6663
余数为好象是4
求2222×1+2222×2+2222×3+……+2222×2222的和除以7所得的余数是多少?
2222×1+2222×6+2222×2+2222×5+2222×3+2222×4+…………
=2222×(1+6)+2222×(2+5)+2222×(3+4)+…………
括号内除以7均能整除 所以同理 最后剩了2222×2220+2222×2221+2222×2222=2222×(2220+2221+2222)=2222×6663
余数为好象是4