已知|4a+3|+(1/2b+a)平方=0.求5(2a+b)平方-3(3a+2b)-3(2a+2b)+2(3a+2b)的值
4a+3=0;
a=-3/4;
b/2+a=0;
b/2=3/4;
b=3/2;
5(2a+b)平方-3(3a+2b)-3(2a+2b)+2(3a+2b)
=5(2a+b)²-(3a+2b)-3(2a+2b)
=5×(2×(-3/4)+3/2)²-（3×(-3/4)+2×(3/2)）-3(2×(-3/4)+2×(3/2))
=0-(3-9/4)-3(3-3/2)
=-3/4-9/2
=-21/4;