如图ABCD是一个矩形,且长与宽的比为3:2,E在BC上,F在CD上,并且三角形ABE三角形ADF,四边形AECF的面积

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  • ∵S△ABE=S△ADF

    ∴1/2AB*BE = 1/2AD*DF

    ∴AD/AB=BE/DF

    又:AD/AB=3/2

    ∴BE/DF=3/2

    令AD=3x,AB=2x;BE=3y,DF=2y,则有:

    FC=DC-DF=AB-DF=2x-2y

    EC=BC-BE=AD-BE=3x-3y

    ∵S△ABE=SAECF=S△AEC+S△ACF

    ∴1/2AB*BE=1/2EC*AB+1/2FC*AD

    即:

    1/2*2x*3y = 1/2*(3x-3y)*2x + 1/2*(2x-2y)*3x

    y=2(x-y)

    2x=3y

    y = 2x/3

    S△AEF=SAECF-S△ECF=S△ABE-S△EFC=1/2*AB*BE-1/2EC*FC

    = 1/2*2x*3y-1/2(3x-3y)*(2x-2y)

    = 1/2*2x*2x-1/2(3x-2x)*(2x-4x/3)

    = 5²/3

    SABCD=AB*AD=3x*2x=6x²

    S△AEF/SABCD = 5²/3 /(6x²) = 5/18