Question

x的四次方+x的三次方-7x的平方-x+6

Answer 1

x的4次方+x³-7x²-x+6

=(x的4次方+x³)-(7x²+7x)+(6x+6)

=x³(x+1)-7x(x+1)+6(x+1)

=(x+1)(x³-7x+6)

=(x+1)[(x³-x²)+(x²-x)-(6x-6)]

=(x+1)[x²(x-1)+x(x-1)-6(x-1)]

=(x+1)(x-1)(x²+x-6)

=(x+1)(x-1)(x+3)(x-2)

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