Question

以24m/s的速度竖直向上抛出质量为m的物体.

Answer 1

(1)上升：a1＝g＋a'＝10+2＝12m/s^2

t1＝v0/a＝24/12s＝2s

h＝0.5*a*t^2＝24m

(2)下降：a2＝g-a'＝8m/s^2

t2＝根号下2*h/a2＝根号6s

v'＝a2*t2＝8倍根号6=19.6m/s