Question

整式加减问题多项式ax^5+bx^3+1,当x=2时,其值为-5,则=-2时,该多项式的值为多少?

Answer 1

多项式ax^5+bx^3+1,当x=2时,其值为-5

∴32a+8b+1=-5

即32a+8b=-6

当x=-2时

ax^5+bx^3+1

=-32a-8b+1

=-(32a+8b)+1

=-(-6)+1

=7