Question

关于高中数学必修一对数函数的计算

Answer 1

㏒a1=0

㏒aa=1

a^㏒aN=N→㏒aN=㏒aX

x=N

∴a^㏒aN=N

a^m=M a^=N

∴MN=a^m+n

m=㏒aM n=㏒aN

m+n=㏒MN

∴㏒aM+㏒aN=㏒aMN同理可证㏒a M-㏒a N=㏒a M/N

㏒a M^n=n㏒a M→㏒a M^n=㏒a M*M……*M

=㏒a M+㏒a M……+㏒a M

= n㏒a M

㏒ab=1/㏒ba →㏒ab=㏒bb/㏒ba

=1/㏒ba

㏒a^n b^m=m/n㏒ab→㏒a^n b^m=㏒ab^m/㏒aa^n

= m㏒ab /n㏒aa

= m/n㏒a